Base | Representation |
---|---|
bin | 11110111010001110011… |
… | …101110100010101011011 |
3 | 21112001200110110112222120 |
4 | 132322032131310111123 |
5 | 234300131112303220 |
6 | 4303444440552323 |
7 | 306314164213140 |
oct | 36721635642533 |
9 | 7461613415876 |
10 | 2124104025435 |
11 | 74991138aa67 |
12 | 2a37ba1826a3 |
13 | 1253c0a92c52 |
14 | 74b42ca83c7 |
15 | 3a3bd405a40 |
hex | 1ee8e77455b |
2124104025435 has 16 divisors (see below), whose sum is σ = 3884075932416. Its totient is φ = 971018983008.
The previous prime is 2124104025401. The next prime is 2124104025451. The reversal of 2124104025435 is 5345204014212.
It is not a de Polignac number, because 2124104025435 - 28 = 2124104025179 is a prime.
It is a super-2 number, since 2×21241040254352 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2124104025396 and 2124104025405.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10114780969 + ... + 10114781178.
It is an arithmetic number, because the mean of its divisors is an integer number (242754745776).
Almost surely, 22124104025435 is an apocalyptic number.
2124104025435 is a deficient number, since it is larger than the sum of its proper divisors (1759971906981).
2124104025435 is a wasteful number, since it uses less digits than its factorization.
2124104025435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20229562162.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 2124104025435 its reverse (5345204014212), we get a palindrome (7469308039647).
The spelling of 2124104025435 in words is "two trillion, one hundred twenty-four billion, one hundred four million, twenty-five thousand, four hundred thirty-five".
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