Base | Representation |
---|---|
bin | 110000010010111111011101… |
… | …100001100111101111101011 |
3 | 1000212002022202101202121002012 |
4 | 300102333131201213233223 |
5 | 210320121342443430323 |
6 | 2031432225404430135 |
7 | 62512132425343235 |
oct | 6022773541475753 |
9 | 1025068671677065 |
10 | 212411324201963 |
11 | 61754155a62047 |
12 | 1b9a68a284834b |
13 | 916a3c0437103 |
14 | 3a64a97749255 |
15 | 198548cb37678 |
hex | c12fdd867beb |
212411324201963 has 2 divisors, whose sum is σ = 212411324201964. Its totient is φ = 212411324201962.
The previous prime is 212411324201959. The next prime is 212411324202211. The reversal of 212411324201963 is 369102423114212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212411324201963 - 22 = 212411324201959 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 212411324201963.
It is not a weakly prime, because it can be changed into another prime (212411324701963) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106205662100981 + 106205662100982.
It is an arithmetic number, because the mean of its divisors is an integer number (106205662100982).
Almost surely, 2212411324201963 is an apocalyptic number.
212411324201963 is a deficient number, since it is larger than the sum of its proper divisors (1).
212411324201963 is an equidigital number, since it uses as much as digits as its factorization.
212411324201963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 41.
The spelling of 212411324201963 in words is "two hundred twelve trillion, four hundred eleven billion, three hundred twenty-four million, two hundred one thousand, nine hundred sixty-three".
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