Base | Representation |
---|---|
bin | 1100010111010011001… |
… | …1110100110000100001 |
3 | 202022021102210112101101 |
4 | 3011310303310300201 |
5 | 11440010230440001 |
6 | 241325314434401 |
7 | 21226536620356 |
oct | 3056463646041 |
9 | 668242715341 |
10 | 212413140001 |
11 | 820a1752a97 |
12 | 35200892a01 |
13 | 17051c4612a |
14 | a3d092462d |
15 | 57d3101a01 |
hex | 3174cf4c21 |
212413140001 has 2 divisors, whose sum is σ = 212413140002. Its totient is φ = 212413140000.
The previous prime is 212413139987. The next prime is 212413140007. The reversal of 212413140001 is 100041314212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 141297051025 + 71116088976 = 375895^2 + 266676^2 .
It is a cyclic number.
It is not a de Polignac number, because 212413140001 - 211 = 212413137953 is a prime.
It is not a weakly prime, because it can be changed into another prime (212413140007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106206570000 + 106206570001.
It is an arithmetic number, because the mean of its divisors is an integer number (106206570001).
Almost surely, 2212413140001 is an apocalyptic number.
It is an amenable number.
212413140001 is a deficient number, since it is larger than the sum of its proper divisors (1).
212413140001 is an equidigital number, since it uses as much as digits as its factorization.
212413140001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 212413140001 its reverse (100041314212), we get a palindrome (312454454213).
The spelling of 212413140001 in words is "two hundred twelve billion, four hundred thirteen million, one hundred forty thousand, one".
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