212414304320331 has 4 divisors (see below), whose sum is σ = 283219072427112. Its totient is φ = 141609536213552.

The previous prime is 212414304320329. The next prime is 212414304320401. The reversal of 212414304320331 is 133023403414212.

212414304320331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 212414304320331 - 2¹ = 212414304320329 is a prime.

It is a super-2 number, since 2×212414304320331² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 212414304320292 and 212414304320301.

It is not an unprimeable number, because it can be changed into a prime (212414304320131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35402384053386 + ... + 35402384053391.

It is an arithmetic number, because the mean of its divisors is an integer number (70804768106778).

Almost surely, 2^{212414304320331} is an apocalyptic number.

212414304320331 is a deficient number, since it is larger than the sum of its proper divisors (70804768106781).

212414304320331 is an equidigital number, since it uses as much as digits as its factorization.

212414304320331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70804768106780.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 212414304320331 its reverse (133023403414212), we get a palindrome (345437707734543).

The spelling of 212414304320331 in words is "two hundred twelve trillion, four hundred fourteen billion, three hundred four million, three hundred twenty thousand, three hundred thirty-one".