Base | Representation |
---|---|
bin | 110000010011000111110101… |
… | …010000111111101010111011 |
3 | 1000212010011221210200221202201 |
4 | 300103013311100333222323 |
5 | 210320243244440300131 |
6 | 2031440313325411031 |
7 | 62512601236131406 |
oct | 6023076520775273 |
9 | 1025104853627681 |
10 | 212420312431291 |
11 | 61757a48643848 |
12 | 1b9a8590a09a77 |
13 | 916b1c36258c3 |
14 | 3a652ab378d3d |
15 | 1985816c8b761 |
hex | c131f543fabb |
212420312431291 has 2 divisors, whose sum is σ = 212420312431292. Its totient is φ = 212420312431290.
The previous prime is 212420312431277. The next prime is 212420312431333. The reversal of 212420312431291 is 192134213024212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212420312431291 - 25 = 212420312431259 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 212420312431291.
It is not a weakly prime, because it can be changed into another prime (212420312432291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106210156215645 + 106210156215646.
It is an arithmetic number, because the mean of its divisors is an integer number (106210156215646).
Almost surely, 2212420312431291 is an apocalyptic number.
212420312431291 is a deficient number, since it is larger than the sum of its proper divisors (1).
212420312431291 is an equidigital number, since it uses as much as digits as its factorization.
212420312431291 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 37.
The spelling of 212420312431291 in words is "two hundred twelve trillion, four hundred twenty billion, three hundred twelve million, four hundred thirty-one thousand, two hundred ninety-one".
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