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2124224020433 is a prime number
BaseRepresentation
bin11110111010010101100…
…111100011111111010001
321112001222211020221011202
4132322111213203333101
5234300402322123213
64303504404520545
7306320152153604
oct36722547437721
97461884227152
102124224020433
11749973098a89
122a38323b0155
1312540c8b77c8
1474b54bc233b
153a3c8c09b58
hex1ee959e3fd1

2124224020433 has 2 divisors, whose sum is σ = 2124224020434. Its totient is φ = 2124224020432.

The previous prime is 2124224020423. The next prime is 2124224020441. The reversal of 2124224020433 is 3340204224212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2060912905744 + 63311114689 = 1435588^2 + 251617^2 .

It is a cyclic number.

It is not a de Polignac number, because 2124224020433 - 224 = 2124207243217 is a prime.

It is a super-4 number, since 4×21242240204334 (a number of 50 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2124224020396 and 2124224020405.

It is not a weakly prime, because it can be changed into another prime (2124224020423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1062112010216 + 1062112010217.

It is an arithmetic number, because the mean of its divisors is an integer number (1062112010217).

Almost surely, 22124224020433 is an apocalyptic number.

It is an amenable number.

2124224020433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2124224020433 is an equidigital number, since it uses as much as digits as its factorization.

2124224020433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 29.

Adding to 2124224020433 its reverse (3340204224212), we get a palindrome (5464428244645).

The spelling of 2124224020433 in words is "two trillion, one hundred twenty-four billion, two hundred twenty-four million, twenty thousand, four hundred thirty-three".