Search a number
-
+
212423222131 is a prime number
BaseRepresentation
bin1100010111010101101…
…0010010001101110011
3202022022010202202110121
43011311122102031303
511440020321102011
6241330314511111
721230021411341
oct3056532221563
9668263682417
10212423222131
11820a740992a
1235204135497
13170540661a3
14a3d1dca991
1557d3e43e71
hex3175692373

212423222131 has 2 divisors, whose sum is σ = 212423222132. Its totient is φ = 212423222130.

The previous prime is 212423222113. The next prime is 212423222173. The reversal of 212423222131 is 131222324212.

Together with previous prime (212423222113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 212423222131 - 211 = 212423220083 is a prime.

It is a super-2 number, since 2×2124232221312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 212423222096 and 212423222105.

It is not a weakly prime, because it can be changed into another prime (212423922131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106211611065 + 106211611066.

It is an arithmetic number, because the mean of its divisors is an integer number (106211611066).

Almost surely, 2212423222131 is an apocalyptic number.

212423222131 is a deficient number, since it is larger than the sum of its proper divisors (1).

212423222131 is an equidigital number, since it uses as much as digits as its factorization.

212423222131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2304, while the sum is 25.

Adding to 212423222131 its reverse (131222324212), we get a palindrome (343645546343).

The spelling of 212423222131 in words is "two hundred twelve billion, four hundred twenty-three million, two hundred twenty-two thousand, one hundred thirty-one".