Base | Representation |
---|---|
bin | 11110111010011010110… |
… | …000001000100001110011 |
3 | 21112002012211022221022002 |
4 | 132322122300020201303 |
5 | 234301041344401311 |
6 | 4303521123004215 |
7 | 306322246242122 |
oct | 36723260104163 |
9 | 7462184287262 |
10 | 2124310153331 |
11 | 749a077789a3 |
12 | 2a385720966b |
13 | 1254246b4512 |
14 | 74b62403ab9 |
15 | 3a3d157093b |
hex | 1ee9ac08873 |
2124310153331 has 2 divisors, whose sum is σ = 2124310153332. Its totient is φ = 2124310153330.
The previous prime is 2124310153307. The next prime is 2124310153417. The reversal of 2124310153331 is 1333510134212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2124310153331 - 26 = 2124310153267 is a prime.
It is a super-2 number, since 2×21243101533312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2124310153294 and 2124310153303.
It is not a weakly prime, because it can be changed into another prime (2124310153631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1062155076665 + 1062155076666.
It is an arithmetic number, because the mean of its divisors is an integer number (1062155076666).
Almost surely, 22124310153331 is an apocalyptic number.
2124310153331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2124310153331 is an equidigital number, since it uses as much as digits as its factorization.
2124310153331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 2124310153331 its reverse (1333510134212), we get a palindrome (3457820287543).
The spelling of 2124310153331 in words is "two trillion, one hundred twenty-four billion, three hundred ten million, one hundred fifty-three thousand, three hundred thirty-one".
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