Base | Representation |
---|---|
bin | 110000010011010001111110… |
… | …001110100111001111011011 |
3 | 1000212011020001120222221012221 |
4 | 300103101332032213033123 |
5 | 210320433044224020443 |
6 | 2031445313544444511 |
7 | 62513435113613113 |
oct | 6023217616471733 |
9 | 1025136046887187 |
10 | 212431200220123 |
11 | 617616254aa735 |
12 | 1b9aa70b179737 |
13 | 916c23a2225c1 |
14 | 3a65a2139a043 |
15 | 1985c52a62eed |
hex | c1347e3a73db |
212431200220123 has 2 divisors, whose sum is σ = 212431200220124. Its totient is φ = 212431200220122.
The previous prime is 212431200220103. The next prime is 212431200220139. The reversal of 212431200220123 is 321022002134212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212431200220123 is a prime.
It is a super-2 number, since 2×2124312002201232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (212431200220103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106215600110061 + 106215600110062.
It is an arithmetic number, because the mean of its divisors is an integer number (106215600110062).
Almost surely, 2212431200220123 is an apocalyptic number.
212431200220123 is a deficient number, since it is larger than the sum of its proper divisors (1).
212431200220123 is an equidigital number, since it uses as much as digits as its factorization.
212431200220123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 212431200220123 its reverse (321022002134212), we get a palindrome (533453202354335).
The spelling of 212431200220123 in words is "two hundred twelve trillion, four hundred thirty-one billion, two hundred million, two hundred twenty thousand, one hundred twenty-three".
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