Base | Representation |
---|---|
bin | 1100010111011000010… |
… | …0111110010111001011 |
3 | 202022022220211022110100 |
4 | 3011312010332113023 |
5 | 11440031202204003 |
6 | 241331354420443 |
7 | 21230215500651 |
oct | 3056604762713 |
9 | 668286738410 |
10 | 212434413003 |
11 | 8210276278a |
12 | 35207a31723 |
13 | 17056483ac7 |
14 | a3d36a0dd1 |
15 | 57d4e04ba3 |
hex | 317613e5cb |
212434413003 has 12 divisors (see below), whose sum is σ = 307542376440. Its totient is φ = 141303248736.
The previous prime is 212434412999. The next prime is 212434413007. The reversal of 212434413003 is 300314434212.
212434413003 is a `hidden beast` number, since 2 + 1 + 243 + 4 + 413 + 0 + 0 + 3 = 666.
It is an interprime number because it is at equal distance from previous prime (212434412999) and next prime (212434413007).
It is not a de Polignac number, because 212434413003 - 22 = 212434412999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (212434413007) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 26636898 + ... + 26644871.
It is an arithmetic number, because the mean of its divisors is an integer number (25628531370).
Almost surely, 2212434413003 is an apocalyptic number.
212434413003 is a deficient number, since it is larger than the sum of its proper divisors (95107963437).
212434413003 is a wasteful number, since it uses less digits than its factorization.
212434413003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53282218 (or 53282215 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 212434413003 its reverse (300314434212), we get a palindrome (512748847215).
The spelling of 212434413003 in words is "two hundred twelve billion, four hundred thirty-four million, four hundred thirteen thousand, three".
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