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212434413003 = 3244353281769
BaseRepresentation
bin1100010111011000010…
…0111110010111001011
3202022022220211022110100
43011312010332113023
511440031202204003
6241331354420443
721230215500651
oct3056604762713
9668286738410
10212434413003
118210276278a
1235207a31723
1317056483ac7
14a3d36a0dd1
1557d4e04ba3
hex317613e5cb

212434413003 has 12 divisors (see below), whose sum is σ = 307542376440. Its totient is φ = 141303248736.

The previous prime is 212434412999. The next prime is 212434413007. The reversal of 212434413003 is 300314434212.

212434413003 is a `hidden beast` number, since 2 + 1 + 243 + 4 + 413 + 0 + 0 + 3 = 666.

It is an interprime number because it is at equal distance from previous prime (212434412999) and next prime (212434413007).

It is not a de Polignac number, because 212434413003 - 22 = 212434412999 is a prime.

It is not an unprimeable number, because it can be changed into a prime (212434413007) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 26636898 + ... + 26644871.

It is an arithmetic number, because the mean of its divisors is an integer number (25628531370).

Almost surely, 2212434413003 is an apocalyptic number.

212434413003 is a deficient number, since it is larger than the sum of its proper divisors (95107963437).

212434413003 is a wasteful number, since it uses less digits than its factorization.

212434413003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53282218 (or 53282215 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 212434413003 its reverse (300314434212), we get a palindrome (512748847215).

The spelling of 212434413003 in words is "two hundred twelve billion, four hundred thirty-four million, four hundred thirteen thousand, three".

Divisors: 1 3 9 443 1329 3987 53281769 159845307 479535921 23603823667 70811471001 212434413003