Base | Representation |
---|---|
bin | 110000010011011011011000… |
… | …010011010101000100100011 |
3 | 1000212012012010120001000100122 |
4 | 300103123120103111010203 |
5 | 210321114241120343301 |
6 | 2031454104142510455 |
7 | 62514243326664401 |
oct | 6023333023250443 |
9 | 1025165116030318 |
10 | 212441301340451 |
11 | 61765939300967 |
12 | 1b9b0669b9542b |
13 | 9170189b56491 |
14 | 3a662dcb22471 |
15 | 198614474781b |
hex | c136d84d5123 |
212441301340451 has 2 divisors, whose sum is σ = 212441301340452. Its totient is φ = 212441301340450.
The previous prime is 212441301340343. The next prime is 212441301340507. The reversal of 212441301340451 is 154043103144212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212441301340451 is a prime.
It is not a weakly prime, because it can be changed into another prime (212441301343451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106220650670225 + 106220650670226.
It is an arithmetic number, because the mean of its divisors is an integer number (106220650670226).
Almost surely, 2212441301340451 is an apocalyptic number.
212441301340451 is a deficient number, since it is larger than the sum of its proper divisors (1).
212441301340451 is an equidigital number, since it uses as much as digits as its factorization.
212441301340451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 212441301340451 its reverse (154043103144212), we get a palindrome (366484404484663).
The spelling of 212441301340451 in words is "two hundred twelve trillion, four hundred forty-one billion, three hundred one million, three hundred forty thousand, four hundred fifty-one".
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