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212453130342433 is a prime number
BaseRepresentation
bin110000010011100110011001…
…010111011001000000100001
31000212020022122221101120112011
4300103212121113121000201
5210321313002331424213
62031503342023232521
762515142423564551
oct6023463127310041
91025208587346464
10212453130342433
116176a959489162
121b9b2a0b5a8741
139171323749636
143a66b01b4b161
1519865d7e8c03d
hexc139995d9021

212453130342433 has 2 divisors, whose sum is σ = 212453130342434. Its totient is φ = 212453130342432.

The previous prime is 212453130342421. The next prime is 212453130342451. The reversal of 212453130342433 is 334243031354212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 163493763915024 + 48959366427409 = 12786468^2 + 6997097^2 .

It is a cyclic number.

It is not a de Polignac number, because 212453130342433 - 225 = 212453096788001 is a prime.

It is not a weakly prime, because it can be changed into another prime (212453130342493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106226565171216 + 106226565171217.

It is an arithmetic number, because the mean of its divisors is an integer number (106226565171217).

Almost surely, 2212453130342433 is an apocalyptic number.

It is an amenable number.

212453130342433 is a deficient number, since it is larger than the sum of its proper divisors (1).

212453130342433 is an equidigital number, since it uses as much as digits as its factorization.

212453130342433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 622080, while the sum is 40.

Adding to 212453130342433 its reverse (334243031354212), we get a palindrome (546696161696645).

The spelling of 212453130342433 in words is "two hundred twelve trillion, four hundred fifty-three billion, one hundred thirty million, three hundred forty-two thousand, four hundred thirty-three".