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21250433110603 = 149142620356447
BaseRepresentation
bin1001101010011110000001…
…00001000101001001001011
32210020112002012222002022111
410311033000201011021023
510241131341334014403
6113110151511203151
74322202354054544
oct465170041051113
983215065862274
1021250433110603
116853292547624
1224725870764b7
13bb1ba42a3808
145367528194cb
1526cb8c46a56d
hex1353c084524b

21250433110603 has 4 divisors (see below), whose sum is σ = 21393053467200. Its totient is φ = 21107812754008.

The previous prime is 21250433110591. The next prime is 21250433110633. The reversal of 21250433110603 is 30601133405212.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21250433110603 - 237 = 21112994157131 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21250433110633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71310178075 + ... + 71310178372.

It is an arithmetic number, because the mean of its divisors is an integer number (5348263366800).

Almost surely, 221250433110603 is an apocalyptic number.

21250433110603 is a deficient number, since it is larger than the sum of its proper divisors (142620356597).

21250433110603 is a wasteful number, since it uses less digits than its factorization.

21250433110603 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 142620356596.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 21250433110603 its reverse (30601133405212), we get a palindrome (51851566515815).

The spelling of 21250433110603 in words is "twenty-one trillion, two hundred fifty billion, four hundred thirty-three million, one hundred ten thousand, six hundred three".

Divisors: 1 149 142620356447 21250433110603