21250614433 has 2 divisors, whose sum is σ = 21250614434. Its totient is φ = 21250614432.

The previous prime is 21250614389. The next prime is 21250614479. The reversal of 21250614433 is 33441605212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18541724224 + 2708890209 = 136168^2 + 52047^2 .

It is a cyclic number.

It is not a de Polignac number, because 21250614433 - 2¹³ = 21250606241 is a prime.

It is a super-2 number, since 2×21250614433² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21250614395 and 21250614404.

It is not a weakly prime, because it can be changed into another prime (21250617433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10625307216 + 10625307217.

It is an arithmetic number, because the mean of its divisors is an integer number (10625307217).

Almost surely, 2^21250614433 is an apocalyptic number.

It is an amenable number.

21250614433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21250614433 is an equidigital number, since it uses as much as digits as its factorization.

21250614433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

The spelling of 21250614433 in words is "twenty-one billion, two hundred fifty million, six hundred fourteen thousand, four hundred thirty-three".