Base | Representation |
---|---|
bin | 1001101010011111010000… |
… | …11101010100011101110011 |
3 | 2210020120210220212211120121 |
4 | 10311033220131110131303 |
5 | 10241134224410312202 |
6 | 113110342205551111 |
7 | 4322225101616233 |
oct | 465175035243563 |
9 | 83216726784517 |
10 | 21251103213427 |
11 | 68535a682680a |
12 | 2472733575497 |
13 | bb1c80075969 |
14 | 5367b780dcc3 |
15 | 26cbcb1d4537 |
hex | 1353e8754773 |
21251103213427 has 2 divisors, whose sum is σ = 21251103213428. Its totient is φ = 21251103213426.
The previous prime is 21251103213413. The next prime is 21251103213437. The reversal of 21251103213427 is 72431230115212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21251103213427 - 27 = 21251103213299 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21251103213392 and 21251103213401.
It is not a weakly prime, because it can be changed into another prime (21251103213437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10625551606713 + 10625551606714.
It is an arithmetic number, because the mean of its divisors is an integer number (10625551606714).
Almost surely, 221251103213427 is an apocalyptic number.
21251103213427 is a deficient number, since it is larger than the sum of its proper divisors (1).
21251103213427 is an equidigital number, since it uses as much as digits as its factorization.
21251103213427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 34.
Adding to 21251103213427 its reverse (72431230115212), we get a palindrome (93682333328639).
The spelling of 21251103213427 in words is "twenty-one trillion, two hundred fifty-one billion, one hundred three million, two hundred thirteen thousand, four hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •