Base | Representation |
---|---|
bin | 11110111011001101000… |
… | …100100000000010011011 |
3 | 21112011101122211201221212 |
4 | 132323031010200002123 |
5 | 234304304003301212 |
6 | 4304141001053335 |
7 | 306352206645416 |
oct | 36731504400233 |
9 | 7464348751855 |
10 | 2125154353307 |
11 | 74a300258927 |
12 | 2a3a51a8724b |
13 | 12552a57182b |
14 | 74c02596b7d |
15 | 3a430728e22 |
hex | 1eecd12009b |
2125154353307 has 2 divisors, whose sum is σ = 2125154353308. Its totient is φ = 2125154353306.
The previous prime is 2125154353253. The next prime is 2125154353363. The reversal of 2125154353307 is 7033534515212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2125154353307 - 210 = 2125154352283 is a prime.
It is not a weakly prime, because it can be changed into another prime (2125154353397) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1062577176653 + 1062577176654.
It is an arithmetic number, because the mean of its divisors is an integer number (1062577176654).
Almost surely, 22125154353307 is an apocalyptic number.
2125154353307 is a deficient number, since it is larger than the sum of its proper divisors (1).
2125154353307 is an equidigital number, since it uses as much as digits as its factorization.
2125154353307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 378000, while the sum is 41.
Adding to 2125154353307 its reverse (7033534515212), we get a palindrome (9158688868519).
The spelling of 2125154353307 in words is "two trillion, one hundred twenty-five billion, one hundred fifty-four million, three hundred fifty-three thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •