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2125335411113 is a prime number
BaseRepresentation
bin11110111011010111110…
…111001011100110101001
321112011212021112102120112
4132323113313023212221
5234310141331123423
64304210545504105
7306356535630635
oct36732767134651
97464767472515
102125335411113
1174a393483282
122a3aa2642035
13125558c26025
1474c1c647dc5
153a441590a78
hex1eed7dcb9a9

2125335411113 has 2 divisors, whose sum is σ = 2125335411114. Its totient is φ = 2125335411112.

The previous prime is 2125335411109. The next prime is 2125335411131. The reversal of 2125335411113 is 3111145335212.

Together with next prime (2125335411131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2099841540889 + 25493870224 = 1449083^2 + 159668^2 .

It is a cyclic number.

It is not a de Polignac number, because 2125335411113 - 22 = 2125335411109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2125335411113.

It is not a weakly prime, because it can be changed into another prime (2125335411713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1062667705556 + 1062667705557.

It is an arithmetic number, because the mean of its divisors is an integer number (1062667705557).

Almost surely, 22125335411113 is an apocalyptic number.

It is an amenable number.

2125335411113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2125335411113 is an equidigital number, since it uses as much as digits as its factorization.

2125335411113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10800, while the sum is 32.

The spelling of 2125335411113 in words is "two trillion, one hundred twenty-five billion, three hundred thirty-five million, four hundred eleven thousand, one hundred thirteen".