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212543731 is a prime number
BaseRepresentation
bin11001010101100…
…10100011110011
3112210221100012001
430222302203303
5413402344411
633031314431
75160410011
oct1452624363
9483840161
10212543731
11a9a80284
125b21ba17
133505992a
14203298b1
15139d5dc1
hexcab28f3

212543731 has 2 divisors, whose sum is σ = 212543732. Its totient is φ = 212543730.

The previous prime is 212543717. The next prime is 212543761. The reversal of 212543731 is 137345212.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 212543731 - 211 = 212541683 is a prime.

It is a super-3 number, since 3×2125437313 (a number of 26 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 212543731.

It is not a weakly prime, because it can be changed into another prime (212543761) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106271865 + 106271866.

It is an arithmetic number, because the mean of its divisors is an integer number (106271866).

Almost surely, 2212543731 is an apocalyptic number.

212543731 is a deficient number, since it is larger than the sum of its proper divisors (1).

212543731 is an equidigital number, since it uses as much as digits as its factorization.

212543731 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5040, while the sum is 28.

The square root of 212543731 is about 14578.8796208762. The cubic root of 212543731 is about 596.7825282253.

Adding to 212543731 its reverse (137345212), we get a palindrome (349888943).

The spelling of 212543731 in words is "two hundred twelve million, five hundred forty-three thousand, seven hundred thirty-one".