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2129260433 = 6823312071
BaseRepresentation
bin111111011101001…
…1110111110010001
312111101120122012112
41332322132332101
513330042313213
6551141235105
7103523262236
oct17672367621
95441518175
102129260433
119a2a03973
124b5102a95
1327c194321
14162b0578d
15c6de6ea8
hex7ee9ef91

2129260433 has 4 divisors (see below), whose sum is σ = 2129579328. Its totient is φ = 2128941540.

The previous prime is 2129260363. The next prime is 2129260459. The reversal of 2129260433 is 3340629212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2129260433 - 214 = 2129244049 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2129260433.

It is not an unprimeable number, because it can be changed into a prime (2129260033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149213 + ... + 162858.

It is an arithmetic number, because the mean of its divisors is an integer number (532394832).

Almost surely, 22129260433 is an apocalyptic number.

It is an amenable number.

2129260433 is a deficient number, since it is larger than the sum of its proper divisors (318895).

2129260433 is an equidigital number, since it uses as much as digits as its factorization.

2129260433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 318894.

The product of its (nonzero) digits is 15552, while the sum is 32.

The square root of 2129260433 is about 46143.9100315524. The cubic root of 2129260433 is about 1286.4994196409.

Adding to 2129260433 its reverse (3340629212), we get a palindrome (5469889645).

The spelling of 2129260433 in words is "two billion, one hundred twenty-nine million, two hundred sixty thousand, four hundred thirty-three".

Divisors: 1 6823 312071 2129260433