Base | Representation |
---|---|
bin | 1100011001011111101… |
… | …0001011111101000001 |
3 | 202100210110212020202101 |
4 | 3012113322023331001 |
5 | 11442212003313213 |
6 | 241503552150401 |
7 | 21250250133652 |
oct | 3062772137501 |
9 | 670713766671 |
10 | 213002010433 |
11 | 8237409a073 |
12 | 35345b38401 |
13 | 17116c45c84 |
14 | a448c11529 |
15 | 5819b71bdd |
hex | 3197e8bf41 |
213002010433 has 2 divisors, whose sum is σ = 213002010434. Its totient is φ = 213002010432.
The previous prime is 213002010427. The next prime is 213002010469. The reversal of 213002010433 is 334010200312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 135989100289 + 77012910144 = 368767^2 + 277512^2 .
It is a cyclic number.
It is not a de Polignac number, because 213002010433 - 29 = 213002009921 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 213002010433.
It is not a weakly prime, because it can be changed into another prime (213002016433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106501005216 + 106501005217.
It is an arithmetic number, because the mean of its divisors is an integer number (106501005217).
Almost surely, 2213002010433 is an apocalyptic number.
It is an amenable number.
213002010433 is a deficient number, since it is larger than the sum of its proper divisors (1).
213002010433 is an equidigital number, since it uses as much as digits as its factorization.
213002010433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 213002010433 its reverse (334010200312), we get a palindrome (547012210745).
The spelling of 213002010433 in words is "two hundred thirteen billion, two million, ten thousand, four hundred thirty-three".
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