Base | Representation |
---|---|
bin | 1001101011111011001010… |
… | …01001110111101101101011 |
3 | 2210102022011021120120002101 |
4 | 10311331211021313231223 |
5 | 10242441300104012204 |
6 | 113145141554314231 |
7 | 4325622520605436 |
oct | 465754511675553 |
9 | 83368137516071 |
10 | 21300439907179 |
11 | 6872514031a84 |
12 | 2480202288977 |
13 | bb6813582c84 |
14 | 538d37dd881d |
15 | 26e117703ea4 |
hex | 135f65277b6b |
21300439907179 has 2 divisors, whose sum is σ = 21300439907180. Its totient is φ = 21300439907178.
The previous prime is 21300439907129. The next prime is 21300439907233. The reversal of 21300439907179 is 97170993400312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21300439907179 - 231 = 21298292423531 is a prime.
It is a super-2 number, since 2×213004399071792 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21300439907129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10650219953589 + 10650219953590.
It is an arithmetic number, because the mean of its divisors is an integer number (10650219953590).
Almost surely, 221300439907179 is an apocalyptic number.
21300439907179 is a deficient number, since it is larger than the sum of its proper divisors (1).
21300439907179 is an equidigital number, since it uses as much as digits as its factorization.
21300439907179 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2571912, while the sum is 55.
The spelling of 21300439907179 in words is "twenty-one trillion, three hundred billion, four hundred thirty-nine million, nine hundred seven thousand, one hundred seventy-nine".
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