Base | Representation |
---|---|
bin | 110000011011101110001111… |
… | …101001010011000101111001 |
3 | 1000221012200102122120012100120 |
4 | 300123232033221103011321 |
5 | 210404434132112404423 |
6 | 2033012013555123453 |
7 | 62603362624160556 |
oct | 6033561751230571 |
9 | 1027180378505316 |
10 | 213011313013113 |
11 | 6196565500325a |
12 | 1ba830298a3589 |
13 | 91b1b5a9778a4 |
14 | 3a85b34319a2d |
15 | 1995da69e4ee3 |
hex | c1bb8fa53179 |
213011313013113 has 4 divisors (see below), whose sum is σ = 284015084017488. Its totient is φ = 142007542008740.
The previous prime is 213011313013069. The next prime is 213011313013183. The reversal of 213011313013113 is 311310313110312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 213011313013113 - 213 = 213011313004921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (213011313013183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35501885502183 + ... + 35501885502188.
It is an arithmetic number, because the mean of its divisors is an integer number (71003771004372).
Almost surely, 2213011313013113 is an apocalyptic number.
It is an amenable number.
213011313013113 is a deficient number, since it is larger than the sum of its proper divisors (71003771004375).
213011313013113 is an equidigital number, since it uses as much as digits as its factorization.
213011313013113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71003771004374.
The product of its (nonzero) digits is 486, while the sum is 24.
Adding to 213011313013113 its reverse (311310313110312), we get a palindrome (524321626123425).
The spelling of 213011313013113 in words is "two hundred thirteen trillion, eleven billion, three hundred thirteen million, thirteen thousand, one hundred thirteen".
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