213013000113 has 4 divisors (see below), whose sum is σ = 284017333488. Its totient is φ = 142008666740.

The previous prime is 213013000099. The next prime is 213013000157. The reversal of 213013000113 is 311000310312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213013000113 - 2⁴ = 213013000097 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 213013000092 and 213013000101.

It is not an unprimeable number, because it can be changed into a prime (213013000163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35502166683 + ... + 35502166688.

It is an arithmetic number, because the mean of its divisors is an integer number (71004333372).

Almost surely, 2^213013000113 is an apocalyptic number.

It is an amenable number.

213013000113 is a deficient number, since it is larger than the sum of its proper divisors (71004333375).

213013000113 is an equidigital number, since it uses as much as digits as its factorization.

213013000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71004333374.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 213013000113 its reverse (311000310312), we get a palindrome (524013310425).

The spelling of 213013000113 in words is "two hundred thirteen billion, thirteen million, one hundred thirteen", and thus it is an aban number.