Base | Representation |
---|---|
bin | 11110111111110110011… |
… | …011001100000110110001 |
3 | 21112122021100010001200221 |
4 | 132333312123030012301 |
5 | 234400013120243004 |
6 | 4310324012013041 |
7 | 306616634615053 |
oct | 36776633140661 |
9 | 7478240101627 |
10 | 2130143134129 |
11 | 7514302a278a |
12 | 2a4a04761181 |
13 | 125b43ca294a |
14 | 75156d778d3 |
15 | 3a6236b6354 |
hex | 1eff66cc1b1 |
2130143134129 has 2 divisors, whose sum is σ = 2130143134130. Its totient is φ = 2130143134128.
The previous prime is 2130143133997. The next prime is 2130143134159. The reversal of 2130143134129 is 9214313410312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1898820612529 + 231322521600 = 1377977^2 + 480960^2 .
It is a cyclic number.
It is not a de Polignac number, because 2130143134129 - 29 = 2130143133617 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2130143134094 and 2130143134103.
It is not a weakly prime, because it can be changed into another prime (2130143134159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065071567064 + 1065071567065.
It is an arithmetic number, because the mean of its divisors is an integer number (1065071567065).
Almost surely, 22130143134129 is an apocalyptic number.
It is an amenable number.
2130143134129 is a deficient number, since it is larger than the sum of its proper divisors (1).
2130143134129 is an equidigital number, since it uses as much as digits as its factorization.
2130143134129 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 2130143134129 in words is "two trillion, one hundred thirty billion, one hundred forty-three million, one hundred thirty-four thousand, one hundred twenty-nine".
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