Base | Representation |
---|---|
bin | 11110111111111010100… |
… | …110011110000110110111 |
3 | 21112122110012221210102201 |
4 | 132333322212132012313 |
5 | 234400134034402221 |
6 | 4310334553445331 |
7 | 306621445305460 |
oct | 36777246360667 |
9 | 7478405853381 |
10 | 2130213200311 |
11 | 7514668a9519 |
12 | 2a4a24110847 |
13 | 125b55665621 |
14 | 751623b5d67 |
15 | 3a629906891 |
hex | 1effa99e1b7 |
2130213200311 has 16 divisors (see below), whose sum is σ = 2487701468160. Its totient is φ = 1786060882080.
The previous prime is 2130213200309. The next prime is 2130213200333. The reversal of 2130213200311 is 1130023120312.
It is a cyclic number.
It is not a de Polignac number, because 2130213200311 - 21 = 2130213200309 is a prime.
It is a super-2 number, since 2×21302132003112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2130213200341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1191816 + ... + 2383453.
It is an arithmetic number, because the mean of its divisors is an integer number (155481341760).
Almost surely, 22130213200311 is an apocalyptic number.
2130213200311 is a deficient number, since it is larger than the sum of its proper divisors (357488267849).
2130213200311 is a wasteful number, since it uses less digits than its factorization.
2130213200311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3577134.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 2130213200311 its reverse (1130023120312), we get a palindrome (3260236320623).
The spelling of 2130213200311 in words is "two trillion, one hundred thirty billion, two hundred thirteen million, two hundred thousand, three hundred eleven".
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