Base | Representation |
---|---|
bin | 1001101011111110010101… |
… | …00010011010001100011011 |
3 | 2210102110112211011211110111 |
4 | 10311333022202122030123 |
5 | 10243003241023314213 |
6 | 113150022435225151 |
7 | 4326012623360425 |
oct | 465771242321433 |
9 | 83373484154414 |
10 | 21302140838683 |
11 | 6873207180aa1 |
12 | 24805b7a481b7 |
13 | bb6a24a97513 |
14 | 539059c83815 |
15 | 26e1b6bdda3d |
hex | 135fca89a31b |
21302140838683 has 2 divisors, whose sum is σ = 21302140838684. Its totient is φ = 21302140838682.
The previous prime is 21302140838621. The next prime is 21302140838707. The reversal of 21302140838683 is 38683804120312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21302140838683 - 233 = 21293550904091 is a prime.
It is a super-3 number, since 3×213021408386833 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (21302144838683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10651070419341 + 10651070419342.
It is an arithmetic number, because the mean of its divisors is an integer number (10651070419342).
Almost surely, 221302140838683 is an apocalyptic number.
21302140838683 is a deficient number, since it is larger than the sum of its proper divisors (1).
21302140838683 is an equidigital number, since it uses as much as digits as its factorization.
21302140838683 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1327104, while the sum is 49.
Adding to 21302140838683 its reverse (38683804120312), we get a palindrome (59985944958995).
The spelling of 21302140838683 in words is "twenty-one trillion, three hundred two billion, one hundred forty million, eight hundred thirty-eight thousand, six hundred eighty-three".
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