Base | Representation |
---|---|
bin | 11111000000000000011… |
… | …101001110111011000001 |
3 | 21112122201001210222211222 |
4 | 133000000131032323001 |
5 | 234400334212121423 |
6 | 4310352423244425 |
7 | 306624050325641 |
oct | 37000035167301 |
9 | 7478631728758 |
10 | 2130311442113 |
11 | 7515072a9a98 |
12 | 2a4a50ba9715 |
13 | 125b6cb11a7a |
14 | 7517146a521 |
15 | 3a6333603c8 |
hex | 1f00074eec1 |
2130311442113 has 2 divisors, whose sum is σ = 2130311442114. Its totient is φ = 2130311442112.
The previous prime is 2130311442079. The next prime is 2130311442157. The reversal of 2130311442113 is 3112441130312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2107804541584 + 22506900529 = 1451828^2 + 150023^2 .
It is a cyclic number.
It is not a de Polignac number, because 2130311442113 - 214 = 2130311425729 is a prime.
It is not a weakly prime, because it can be changed into another prime (2130311441113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065155721056 + 1065155721057.
It is an arithmetic number, because the mean of its divisors is an integer number (1065155721057).
Almost surely, 22130311442113 is an apocalyptic number.
It is an amenable number.
2130311442113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2130311442113 is an equidigital number, since it uses as much as digits as its factorization.
2130311442113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 2130311442113 its reverse (3112441130312), we get a palindrome (5242752572425).
The spelling of 2130311442113 in words is "two trillion, one hundred thirty billion, three hundred eleven million, four hundred forty-two thousand, one hundred thirteen".
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