213033311320033 has 4 divisors (see below), whose sum is σ = 213033350913988. Its totient is φ = 213033271726080.

The previous prime is 213033311320019. The next prime is 213033311320117. The reversal of 213033311320033 is 330023113330312.

213033311320033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 182576522119744 + 30456789200289 = 13512088^2 + 5518767^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-213033311320033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213033311319983 and 213033311320010.

It is not an unprimeable number, because it can be changed into a prime (213033311320633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10163808 + ... + 23008033.

It is an arithmetic number, because the mean of its divisors is an integer number (53258337728497).

Almost surely, 2^{213033311320033} is an apocalyptic number.

It is an amenable number.

213033311320033 is a deficient number, since it is larger than the sum of its proper divisors (39593955).

213033311320033 is an equidigital number, since it uses as much as digits as its factorization.

213033311320033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39593954.

The product of its (nonzero) digits is 8748, while the sum is 28.

Adding to 213033311320033 its reverse (330023113330312), we get a palindrome (543056424650345).

The spelling of 213033311320033 in words is "two hundred thirteen trillion, thirty-three billion, three hundred eleven million, three hundred twenty thousand, thirty-three".