Base | Representation |
---|---|
bin | 10011110101110101… |
… | …111000000100100011 |
3 | 2000222202000011221011 |
4 | 103311311320010203 |
5 | 322112412113103 |
6 | 13442003241351 |
7 | 1352641333453 |
oct | 236565700443 |
9 | 60882004834 |
10 | 21304410403 |
11 | 9042869951 |
12 | 4166979257 |
13 | 20169c8203 |
14 | 1061633d63 |
15 | 84a52cd6d |
hex | 4f5d78123 |
21304410403 has 2 divisors, whose sum is σ = 21304410404. Its totient is φ = 21304410402.
The previous prime is 21304410377. The next prime is 21304410419. The reversal of 21304410403 is 30401440312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21304410403 - 29 = 21304409891 is a prime.
It is a super-3 number, since 3×213044104033 (a number of 32 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (21304410443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10652205201 + 10652205202.
It is an arithmetic number, because the mean of its divisors is an integer number (10652205202).
Almost surely, 221304410403 is an apocalyptic number.
21304410403 is a deficient number, since it is larger than the sum of its proper divisors (1).
21304410403 is an equidigital number, since it uses as much as digits as its factorization.
21304410403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 21304410403 its reverse (30401440312), we get a palindrome (51705850715).
The spelling of 21304410403 in words is "twenty-one billion, three hundred four million, four hundred ten thousand, four hundred three".
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