Base | Representation |
---|---|
bin | 1100011001101100101… |
… | …1100010010100100011 |
3 | 202100221022010102120101 |
4 | 3012123023202110203 |
5 | 11442320030441042 |
6 | 241513232323231 |
7 | 21251514454063 |
oct | 3063313422443 |
9 | 670838112511 |
10 | 213056890147 |
11 | 823a2073002 |
12 | 353603a3517 |
13 | 1712541c48a |
14 | a4522193a3 |
15 | 581e8b26b7 |
hex | 319b2e2523 |
213056890147 has 2 divisors, whose sum is σ = 213056890148. Its totient is φ = 213056890146.
The previous prime is 213056890091. The next prime is 213056890153. The reversal of 213056890147 is 741098650312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213056890147 - 219 = 213056365859 is a prime.
It is a super-3 number, since 3×2130568901473 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 213056890097 and 213056890106.
It is not a weakly prime, because it can be changed into another prime (213056890187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106528445073 + 106528445074.
It is an arithmetic number, because the mean of its divisors is an integer number (106528445074).
It is a 1-persistent number, because it is pandigital, but 2⋅213056890147 = 426113780294 is not.
Almost surely, 2213056890147 is an apocalyptic number.
213056890147 is a deficient number, since it is larger than the sum of its proper divisors (1).
213056890147 is an equidigital number, since it uses as much as digits as its factorization.
213056890147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 46.
The spelling of 213056890147 in words is "two hundred thirteen billion, fifty-six million, eight hundred ninety thousand, one hundred forty-seven".
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