Base | Representation |
---|---|
bin | 1100011001110110110… |
… | …1101100111000110001 |
3 | 202101001021010012011021 |
4 | 3012131231230320301 |
5 | 11442411421311003 |
6 | 241521351415441 |
7 | 21252542006521 |
oct | 3063555547061 |
9 | 671037105137 |
10 | 213099400753 |
11 | 82414068938 |
12 | 35372684581 |
13 | 17131184995 |
14 | a457b23681 |
15 | 58234ad2bd |
hex | 319db6ce31 |
213099400753 has 2 divisors, whose sum is σ = 213099400754. Its totient is φ = 213099400752.
The previous prime is 213099400711. The next prime is 213099400831. The reversal of 213099400753 is 357004990312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 199752681969 + 13346718784 = 446937^2 + 115528^2 .
It is a cyclic number.
It is not a de Polignac number, because 213099400753 - 217 = 213099269681 is a prime.
It is a super-3 number, since 3×2130994007533 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (213099400453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106549700376 + 106549700377.
It is an arithmetic number, because the mean of its divisors is an integer number (106549700377).
Almost surely, 2213099400753 is an apocalyptic number.
It is an amenable number.
213099400753 is a deficient number, since it is larger than the sum of its proper divisors (1).
213099400753 is an equidigital number, since it uses as much as digits as its factorization.
213099400753 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 204120, while the sum is 43.
The spelling of 213099400753 in words is "two hundred thirteen billion, ninety-nine million, four hundred thousand, seven hundred fifty-three".
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