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213099400753 is a prime number
BaseRepresentation
bin1100011001110110110…
…1101100111000110001
3202101001021010012011021
43012131231230320301
511442411421311003
6241521351415441
721252542006521
oct3063555547061
9671037105137
10213099400753
1182414068938
1235372684581
1317131184995
14a457b23681
1558234ad2bd
hex319db6ce31

213099400753 has 2 divisors, whose sum is σ = 213099400754. Its totient is φ = 213099400752.

The previous prime is 213099400711. The next prime is 213099400831. The reversal of 213099400753 is 357004990312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 199752681969 + 13346718784 = 446937^2 + 115528^2 .

It is a cyclic number.

It is not a de Polignac number, because 213099400753 - 217 = 213099269681 is a prime.

It is a super-3 number, since 3×2130994007533 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (213099400453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106549700376 + 106549700377.

It is an arithmetic number, because the mean of its divisors is an integer number (106549700377).

Almost surely, 2213099400753 is an apocalyptic number.

It is an amenable number.

213099400753 is a deficient number, since it is larger than the sum of its proper divisors (1).

213099400753 is an equidigital number, since it uses as much as digits as its factorization.

213099400753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 204120, while the sum is 43.

The spelling of 213099400753 in words is "two hundred thirteen billion, ninety-nine million, four hundred thousand, seven hundred fifty-three".