Base | Representation |
---|---|
bin | 110000011101000010110011… |
… | …110000101001100011101011 |
3 | 1000221112100210200012021222100 |
4 | 300131002303300221203223 |
5 | 210412431111441430011 |
6 | 2033121432003024443 |
7 | 62613056011255233 |
oct | 6035026360514353 |
9 | 1027470720167870 |
10 | 213102113233131 |
11 | 619a010a3a5501 |
12 | 1ba9874a66b123 |
13 | 91ba59b4c8c25 |
14 | 3a8a2a95dccc3 |
15 | 199841d23dd56 |
hex | c1d0b3c298eb |
213102113233131 has 48 divisors (see below), whose sum is σ = 309090452186880. Its totient is φ = 141480170112960.
The previous prime is 213102113233127. The next prime is 213102113233151. The reversal of 213102113233131 is 131332311201312.
213102113233131 is a `hidden beast` number, since 2 + 1 + 3 + 1 + 0 + 21 + 1 + 323 + 313 + 1 = 666.
It is not a de Polignac number, because 213102113233131 - 22 = 213102113233127 is a prime.
It is a super-2 number, since 2×2131021132331312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 213102113233095 and 213102113233104.
It is not an unprimeable number, because it can be changed into a prime (213102113233151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 8442015396 + ... + 8442040638.
It is an arithmetic number, because the mean of its divisors is an integer number (6439384420560).
Almost surely, 2213102113233131 is an apocalyptic number.
213102113233131 is a deficient number, since it is larger than the sum of its proper divisors (95988338953749).
213102113233131 is a wasteful number, since it uses less digits than its factorization.
213102113233131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28896 (or 28893 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 27.
Adding to 213102113233131 its reverse (131332311201312), we get a palindrome (344434424434443).
The spelling of 213102113233131 in words is "two hundred thirteen trillion, one hundred two billion, one hundred thirteen million, two hundred thirty-three thousand, one hundred thirty-one".
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