213102121133113 has 4 divisors (see below), whose sum is σ = 213163024858000. Its totient is φ = 213041217408228.

The previous prime is 213102121133093. The next prime is 213102121133129. The reversal of 213102121133113 is 311331121201312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-213102121133113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (213102125133113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30451857195 + ... + 30451864192.

It is an arithmetic number, because the mean of its divisors is an integer number (53290756214500).

Almost surely, 2^{213102121133113} is an apocalyptic number.

It is an amenable number.

213102121133113 is a deficient number, since it is larger than the sum of its proper divisors (60903724887).

213102121133113 is an equidigital number, since it uses as much as digits as its factorization.

213102121133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60903724886.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 213102121133113 its reverse (311331121201312), we get a palindrome (524433242334425).

The spelling of 213102121133113 in words is "two hundred thirteen trillion, one hundred two billion, one hundred twenty-one million, one hundred thirty-three thousand, one hundred thirteen".