Base | Representation |
---|---|
bin | 11111000000101010111… |
… | …000000110111001111001 |
3 | 21112201112122222111102020 |
4 | 133000222320012321321 |
5 | 234403313410131413 |
6 | 4310551205225053 |
7 | 306650511510264 |
oct | 37005270067171 |
9 | 7481478874366 |
10 | 2131023130233 |
11 | 751842001898 |
12 | 2a500b402189 |
13 | 125c543b41ba |
14 | 751dbba7cdb |
15 | 3a675a90c23 |
hex | 1f02ae06e79 |
2131023130233 has 4 divisors (see below), whose sum is σ = 2841364173648. Its totient is φ = 1420682086820.
The previous prime is 2131023130207. The next prime is 2131023130241. The reversal of 2131023130233 is 3320313201312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2131023130233 - 212 = 2131023126137 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2131023130273) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355170521703 + ... + 355170521708.
It is an arithmetic number, because the mean of its divisors is an integer number (710341043412).
Almost surely, 22131023130233 is an apocalyptic number.
It is an amenable number.
2131023130233 is a deficient number, since it is larger than the sum of its proper divisors (710341043415).
2131023130233 is an equidigital number, since it uses as much as digits as its factorization.
2131023130233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 710341043414.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 2131023130233 its reverse (3320313201312), we get a palindrome (5451336331545).
The spelling of 2131023130233 in words is "two trillion, one hundred thirty-one billion, twenty-three million, one hundred thirty thousand, two hundred thirty-three".
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