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21310312223113 = 67318064361539
BaseRepresentation
bin1001101100001101100011…
…00101110001000110001001
32210110020122022002011121021
410312012301211301012021
510243122004412114423
6113153453340312441
74326422255113564
oct466066145610611
983406568064537
1021310312223113
11687671a767071
1224820b8542721
13bb7727985b34
145395d32014db
1526e4e428e95d
hex1361b1971189

21310312223113 has 4 divisors (see below), whose sum is σ = 21628376584720. Its totient is φ = 20992247861508.

The previous prime is 21310312223069. The next prime is 21310312223141. The reversal of 21310312223113 is 31132221301312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21310312223113 - 233 = 21301722288521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21310312223513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159032180703 + ... + 159032180836.

It is an arithmetic number, because the mean of its divisors is an integer number (5407094146180).

Almost surely, 221310312223113 is an apocalyptic number.

It is an amenable number.

21310312223113 is a deficient number, since it is larger than the sum of its proper divisors (318064361607).

21310312223113 is an equidigital number, since it uses as much as digits as its factorization.

21310312223113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 318064361606.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 21310312223113 its reverse (31132221301312), we get a palindrome (52442533524425).

The spelling of 21310312223113 in words is "twenty-one trillion, three hundred ten billion, three hundred twelve million, two hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 67 318064361539 21310312223113