Base | Representation |
---|---|
bin | 110000011101001011010111… |
… | …011101000000001110000011 |
3 | 1000221120020112001110212221111 |
4 | 300131023113131000032003 |
5 | 210413103421302404233 |
6 | 2033125551450104151 |
7 | 62613532505416453 |
oct | 6035132735001603 |
9 | 1027506461425844 |
10 | 213111301997443 |
11 | 619a3aa51a50a3 |
12 | 1ba9a493a1b057 |
13 | 91bb4040cb385 |
14 | 3a8a8dbb0dd63 |
15 | 19987a9ca5acd |
hex | c1d2d7740383 |
213111301997443 has 2 divisors, whose sum is σ = 213111301997444. Its totient is φ = 213111301997442.
The previous prime is 213111301997411. The next prime is 213111301997453. The reversal of 213111301997443 is 344799103111312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213111301997443 - 25 = 213111301997411 is a prime.
It is not a weakly prime, because it can be changed into another prime (213111301997453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106555650998721 + 106555650998722.
It is an arithmetic number, because the mean of its divisors is an integer number (106555650998722).
Almost surely, 2213111301997443 is an apocalyptic number.
213111301997443 is a deficient number, since it is larger than the sum of its proper divisors (1).
213111301997443 is an equidigital number, since it uses as much as digits as its factorization.
213111301997443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 489888, while the sum is 49.
The spelling of 213111301997443 in words is "two hundred thirteen trillion, one hundred eleven billion, three hundred one million, nine hundred ninety-seven thousand, four hundred forty-three".
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