213112023433 has 4 divisors (see below), whose sum is σ = 213133852800. Its totient is φ = 213090194068.

The previous prime is 213112023419. The next prime is 213112023457. The reversal of 213112023433 is 334320211312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213112023433 - 2¹³ = 213112015241 is a prime.

It is a super-2 number, since 2×213112023433² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213112023398 and 213112023407.

It is not an unprimeable number, because it can be changed into a prime (213112023403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10900033 + ... + 10919566.

It is an arithmetic number, because the mean of its divisors is an integer number (53283463200).

Almost surely, 2^213112023433 is an apocalyptic number.

It is an amenable number.

213112023433 is a deficient number, since it is larger than the sum of its proper divisors (21829367).

213112023433 is an equidigital number, since it uses as much as digits as its factorization.

213112023433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21829366.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 213112023433 its reverse (334320211312), we get a palindrome (547432234745).

The spelling of 213112023433 in words is "two hundred thirteen billion, one hundred twelve million, twenty-three thousand, four hundred thirty-three".