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21311299951057 is a prime number
BaseRepresentation
bin1001101100001111011000…
…11101101001100111010001
32210110100012010122221121201
410312013230131221213101
510243131020241413212
6113154135342551201
74326455610503104
oct466075435514721
983410163587551
1021311299951057
116877087268756
122482333298501
13bb78544b723c
1453968847673b
1526e550d49b57
hex1361ec7699d1

21311299951057 has 2 divisors, whose sum is σ = 21311299951058. Its totient is φ = 21311299951056.

The previous prime is 21311299951027. The next prime is 21311299951063. The reversal of 21311299951057 is 75015999211312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17692463350081 + 3618836600976 = 4206241^2 + 1902324^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21311299951057 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21311299950989 and 21311299951007.

It is not a weakly prime, because it can be changed into another prime (21311299951027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10655649975528 + 10655649975529.

It is an arithmetic number, because the mean of its divisors is an integer number (10655649975529).

Almost surely, 221311299951057 is an apocalyptic number.

It is an amenable number.

21311299951057 is a deficient number, since it is larger than the sum of its proper divisors (1).

21311299951057 is an equidigital number, since it uses as much as digits as its factorization.

21311299951057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1530900, while the sum is 55.

The spelling of 21311299951057 in words is "twenty-one trillion, three hundred eleven billion, two hundred ninety-nine million, nine hundred fifty-one thousand, fifty-seven".