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2131131233113 = 6310033377371
BaseRepresentation
bin11111000000110001010…
…100011111001101011001
321112201211012101200200121
4133000301110133031121
5234404024043424423
64311010030233241
7306653263411111
oct37006124371531
97481735350617
102131131233113
11751898028113
122a503b655821
13125c70903bbc
147520c2a8041
153a6802e645d
hex1f03151f359

2131131233113 has 4 divisors (see below), whose sum is σ = 2131135241488. Its totient is φ = 2131127224740.

The previous prime is 2131131233087. The next prime is 2131131233149. The reversal of 2131131233113 is 3113321311312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2131131233113 - 237 = 1993692279641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2131131233213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1057683 + ... + 2319688.

It is an arithmetic number, because the mean of its divisors is an integer number (532783810372).

Almost surely, 22131131233113 is an apocalyptic number.

It is an amenable number.

2131131233113 is a deficient number, since it is larger than the sum of its proper divisors (4008375).

2131131233113 is an equidigital number, since it uses as much as digits as its factorization.

2131131233113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4008374.

The product of its digits is 972, while the sum is 25.

Adding to 2131131233113 its reverse (3113321311312), we get a palindrome (5244452544425).

The spelling of 2131131233113 in words is "two trillion, one hundred thirty-one billion, one hundred thirty-one million, two hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 631003 3377371 2131131233113