Base | Representation |
---|---|
bin | 1100011001111010001… |
… | …0011011000000110011 |
3 | 202101002020010100012121 |
4 | 3012132202123000303 |
5 | 11442423441034141 |
6 | 241523003535111 |
7 | 21253100330344 |
oct | 3063642330063 |
9 | 671066110177 |
10 | 213113221171 |
11 | 82420948374 |
12 | 3537722a497 |
13 | 17133cb3446 |
14 | a4598c00cb |
15 | 58247dd1d1 |
hex | 319e89b033 |
213113221171 has 2 divisors, whose sum is σ = 213113221172. Its totient is φ = 213113221170.
The previous prime is 213113221159. The next prime is 213113221219. The reversal of 213113221171 is 171122311312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213113221171 - 215 = 213113188403 is a prime.
It is a super-2 number, since 2×2131132211712 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (213113221121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106556610585 + 106556610586.
It is an arithmetic number, because the mean of its divisors is an integer number (106556610586).
Almost surely, 2213113221171 is an apocalyptic number.
213113221171 is a deficient number, since it is larger than the sum of its proper divisors (1).
213113221171 is an equidigital number, since it uses as much as digits as its factorization.
213113221171 is an evil number, because the sum of its binary digits is even.
The product of its digits is 504, while the sum is 25.
Adding to 213113221171 its reverse (171122311312), we get a palindrome (384235532483).
The spelling of 213113221171 in words is "two hundred thirteen billion, one hundred thirteen million, two hundred twenty-one thousand, one hundred seventy-one".
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