Base | Representation |
---|---|
bin | 110000011101001101010000… |
… | …100001000011101000010010 |
3 | 1000221120102202121100202010202 |
4 | 300131031100201003220102 |
5 | 210413122101233244442 |
6 | 2033130525203455202 |
7 | 62613634030503404 |
oct | 6035152041035022 |
9 | 1027512677322122 |
10 | 213113333103122 |
11 | 619a4947757931 |
12 | 1ba9a960087502 |
13 | 91bb668b46a5a |
14 | 3a8aa51784b74 |
15 | 199887825ec32 |
hex | c1d350843a12 |
213113333103122 has 8 divisors (see below), whose sum is σ = 327104185693296. Its totient is φ = 104078604538692.
The previous prime is 213113333103113. The next prime is 213113333103133. The reversal of 213113333103122 is 221301333311312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×2131133331031223 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1239031006328 + ... + 1239031006499.
It is an arithmetic number, because the mean of its divisors is an integer number (40888023211662).
Almost surely, 2213113333103122 is an apocalyptic number.
213113333103122 is a deficient number, since it is larger than the sum of its proper divisors (113990852590174).
213113333103122 is a wasteful number, since it uses less digits than its factorization.
213113333103122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2478062012872.
The product of its (nonzero) digits is 5832, while the sum is 29.
Adding to 213113333103122 its reverse (221301333311312), we get a palindrome (434414666414434).
The spelling of 213113333103122 in words is "two hundred thirteen trillion, one hundred thirteen billion, three hundred thirty-three million, one hundred three thousand, one hundred twenty-two".
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