Base | Representation |
---|---|
bin | 10011110110010010… |
… | …100011100000101001 |
3 | 2001000021011010122001 |
4 | 103312102203200221 |
5 | 322121323201421 |
6 | 13442432331001 |
7 | 1353062254633 |
oct | 236622434051 |
9 | 61007133561 |
10 | 21311928361 |
11 | 9047034239 |
12 | 41693a3a61 |
13 | 201842b0c9 |
14 | 106262da53 |
15 | 84b015691 |
hex | 4f64a3829 |
21311928361 has 4 divisors (see below), whose sum is σ = 21630016912. Its totient is φ = 20993839812.
The previous prime is 21311928353. The next prime is 21311928373. The reversal of 21311928361 is 16382911312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 21311928361 - 23 = 21311928353 is a prime.
It is a super-2 number, since 2×213119283612 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 21311928361.
It is not an unprimeable number, because it can be changed into a prime (21311908361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159044175 + ... + 159044308.
It is an arithmetic number, because the mean of its divisors is an integer number (5407504228).
Almost surely, 221311928361 is an apocalyptic number.
It is an amenable number.
21311928361 is a deficient number, since it is larger than the sum of its proper divisors (318088551).
21311928361 is an equidigital number, since it uses as much as digits as its factorization.
21311928361 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 318088550.
The product of its digits is 15552, while the sum is 37.
The spelling of 21311928361 in words is "twenty-one billion, three hundred eleven million, nine hundred twenty-eight thousand, three hundred sixty-one".
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