Base | Representation |
---|---|
bin | 11111000000110101100… |
… | …111011100011011011011 |
3 | 21112202000020000122101221 |
4 | 133000311213130123123 |
5 | 234404201021430243 |
6 | 4311021123152511 |
7 | 306655130151502 |
oct | 37006547343333 |
9 | 7482006018357 |
10 | 2131203311323 |
11 | 751924788589 |
12 | 2a505b815737 |
13 | 125c8281c628 |
14 | 75217aab839 |
15 | 3a6867d2bed |
hex | 1f0359dc6db |
2131203311323 has 2 divisors, whose sum is σ = 2131203311324. Its totient is φ = 2131203311322.
The previous prime is 2131203311311. The next prime is 2131203311333. The reversal of 2131203311323 is 3231133021312.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2131203311323 is a prime.
It is not a weakly prime, because it can be changed into another prime (2131203311333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065601655661 + 1065601655662.
It is an arithmetic number, because the mean of its divisors is an integer number (1065601655662).
Almost surely, 22131203311323 is an apocalyptic number.
2131203311323 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131203311323 is an equidigital number, since it uses as much as digits as its factorization.
2131203311323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 2131203311323 its reverse (3231133021312), we get a palindrome (5362336332635).
The spelling of 2131203311323 in words is "two trillion, one hundred thirty-one billion, two hundred three million, three hundred eleven thousand, three hundred twenty-three".
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