Base | Representation |
---|---|
bin | 1001101100010000111000… |
… | …01101100010010010010111 |
3 | 2210110102020222001010121102 |
4 | 10312020130031202102113 |
5 | 10243134140331024421 |
6 | 113154351040540315 |
7 | 4326514505544230 |
oct | 466103415422227 |
9 | 83412228033542 |
10 | 21312101033111 |
11 | 6877458478539 |
12 | 248251762169b |
13 | bb79514587a5 |
14 | 539722a04087 |
15 | 26e59b33760b |
hex | 13621c362497 |
21312101033111 has 16 divisors (see below), whose sum is σ = 24950946736128. Its totient is φ = 17821827230400.
The previous prime is 21312101033107. The next prime is 21312101033123. The reversal of 21312101033111 is 11133010121312.
It is a cyclic number.
It is not a de Polignac number, because 21312101033111 - 22 = 21312101033107 is a prime.
It is a super-3 number, since 3×213121010331113 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21312101033141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 55043966 + ... + 55429796.
It is an arithmetic number, because the mean of its divisors is an integer number (1559434171008).
Almost surely, 221312101033111 is an apocalyptic number.
21312101033111 is a deficient number, since it is larger than the sum of its proper divisors (3638845703017).
21312101033111 is a wasteful number, since it uses less digits than its factorization.
21312101033111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 578342.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 21312101033111 its reverse (11133010121312), we get a palindrome (32445111154423).
The spelling of 21312101033111 in words is "twenty-one trillion, three hundred twelve billion, one hundred one million, thirty-three thousand, one hundred eleven".
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