Base | Representation |
---|---|
bin | 11111000000110110001… |
… | …001110100010101010011 |
3 | 21112202000211222102220120 |
4 | 133000312021310111103 |
5 | 234404210323302011 |
6 | 4311022044241323 |
7 | 306655266561204 |
oct | 37006611642523 |
9 | 7482024872816 |
10 | 2131212322131 |
11 | 751929882532 |
12 | 2a5062840243 |
13 | 125c84655b79 |
14 | 75218d755ab |
15 | 3a6874b2a06 |
hex | 1f036274553 |
2131212322131 has 4 divisors (see below), whose sum is σ = 2841616429512. Its totient is φ = 1420808214752.
The previous prime is 2131212322123. The next prime is 2131212322133. The reversal of 2131212322131 is 1312232121312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2131212322131 - 23 = 2131212322123 is a prime.
It is a super-2 number, since 2×21312123221312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2131212322133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355202053686 + ... + 355202053691.
It is an arithmetic number, because the mean of its divisors is an integer number (710404107378).
Almost surely, 22131212322131 is an apocalyptic number.
2131212322131 is a deficient number, since it is larger than the sum of its proper divisors (710404107381).
2131212322131 is an equidigital number, since it uses as much as digits as its factorization.
2131212322131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 710404107380.
The product of its digits is 864, while the sum is 24.
Adding to 2131212322131 its reverse (1312232121312), we get a palindrome (3443444443443).
The spelling of 2131212322131 in words is "two trillion, one hundred thirty-one billion, two hundred twelve million, three hundred twenty-two thousand, one hundred thirty-one".
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