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2131242143441 is a prime number
BaseRepresentation
bin11111000000110111111…
…011100100111011010001
321112202002221002112001112
4133000313323210323101
5234404240442042231
64311025031343105
7306656111213615
oct37006773447321
97482087075045
102131242143441
117519446a0744
122a5070821a95
13125c8a897708
147521ccd9345
153a689e0392b
hex1f037ee4ed1

2131242143441 has 2 divisors, whose sum is σ = 2131242143442. Its totient is φ = 2131242143440.

The previous prime is 2131242143423. The next prime is 2131242143483. The reversal of 2131242143441 is 1443412421312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1684388665600 + 446853477841 = 1297840^2 + 668471^2 .

It is a cyclic number.

It is not a de Polignac number, because 2131242143441 - 26 = 2131242143377 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2131242143398 and 2131242143407.

It is not a weakly prime, because it can be changed into another prime (2131242143341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065621071720 + 1065621071721.

It is an arithmetic number, because the mean of its divisors is an integer number (1065621071721).

Almost surely, 22131242143441 is an apocalyptic number.

It is an amenable number.

2131242143441 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131242143441 is an equidigital number, since it uses as much as digits as its factorization.

2131242143441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18432, while the sum is 32.

Adding to 2131242143441 its reverse (1443412421312), we get a palindrome (3574654564753).

The spelling of 2131242143441 in words is "two trillion, one hundred thirty-one billion, two hundred forty-two million, one hundred forty-three thousand, four hundred forty-one".