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21313121221081 is a prime number
BaseRepresentation
bin1001101100010010110010…
…00001001111100111011001
32210110111220001201001102001
410312021121001033213121
510243143233013033311
6113155040203041001
74326552004156204
oct466113101174731
983414801631361
1021313121221081
11687793132a898
122482761210161
13bb7a84913801
145397bc2c893b
1526e60aba54c1
hex13625904f9d9

21313121221081 has 2 divisors, whose sum is σ = 21313121221082. Its totient is φ = 21313121221080.

The previous prime is 21313121221043. The next prime is 21313121221099. The reversal of 21313121221081 is 18012212131312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21313041726025 + 79495056 = 4616605^2 + 8916^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21313121221081 is a prime.

It is a super-2 number, since 2×213131212210812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21313121221681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656560610540 + 10656560610541.

It is an arithmetic number, because the mean of its divisors is an integer number (10656560610541).

Almost surely, 221313121221081 is an apocalyptic number.

It is an amenable number.

21313121221081 is a deficient number, since it is larger than the sum of its proper divisors (1).

21313121221081 is an equidigital number, since it uses as much as digits as its factorization.

21313121221081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 28.

Adding to 21313121221081 its reverse (18012212131312), we get a palindrome (39325333352393).

The spelling of 21313121221081 in words is "twenty-one trillion, three hundred thirteen billion, one hundred twenty-one million, two hundred twenty-one thousand, eighty-one".