Base | Representation |
---|---|
bin | 1100011010000000101… |
… | …0010001010100010001 |
3 | 202101011010100102111120 |
4 | 3012200022101110101 |
5 | 11443002423210213 |
6 | 241525415232453 |
7 | 21253550612430 |
oct | 3064012212421 |
9 | 671133312446 |
10 | 213140444433 |
11 | 82435251634 |
12 | 35384378729 |
13 | 17139825597 |
14 | a45d369117 |
15 | 5826db9423 |
hex | 31a0291511 |
213140444433 has 16 divisors (see below), whose sum is σ = 324797991936. Its totient is φ = 121789832400.
The previous prime is 213140444401. The next prime is 213140444453. The reversal of 213140444433 is 334444041312.
It is not a de Polignac number, because 213140444433 - 25 = 213140444401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 213140444394 and 213140444403.
It is not an unprimeable number, because it can be changed into a prime (213140444453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 402660 + ... + 767082.
It is an arithmetic number, because the mean of its divisors is an integer number (20299874496).
Almost surely, 2213140444433 is an apocalyptic number.
It is an amenable number.
213140444433 is a deficient number, since it is larger than the sum of its proper divisors (111657547503).
213140444433 is a wasteful number, since it uses less digits than its factorization.
213140444433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 392284.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 213140444433 its reverse (334444041312), we get a palindrome (547584485745).
The spelling of 213140444433 in words is "two hundred thirteen billion, one hundred forty million, four hundred forty-four thousand, four hundred thirty-three".
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