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213200343001 = 792698738519
BaseRepresentation
bin1100011010001110111…
…0110000111111011001
3202101022022001120220001
43012203232300333121
511443113241434001
6241535355133001
721255206005012
oct3064356607731
9671268046801
10213200343001
1182466043288
12353a0444161
1317149068319
14a4672bc009
15582c29c001
hex31a3bb0fd9

213200343001 has 4 divisors (see below), whose sum is σ = 215899081600. Its totient is φ = 210501604404.

The previous prime is 213200342933. The next prime is 213200343127. The reversal of 213200343001 is 100343002312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213200343001 - 221 = 213198245849 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 213200343001.

It is not an unprimeable number, because it can be changed into a prime (213200343701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1349369181 + ... + 1349369338.

It is an arithmetic number, because the mean of its divisors is an integer number (53974770400).

Almost surely, 2213200343001 is an apocalyptic number.

It is an amenable number.

213200343001 is a deficient number, since it is larger than the sum of its proper divisors (2698738599).

213200343001 is an equidigital number, since it uses as much as digits as its factorization.

213200343001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2698738598.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 213200343001 its reverse (100343002312), we get a palindrome (313543345313).

The spelling of 213200343001 in words is "two hundred thirteen billion, two hundred million, three hundred forty-three thousand, one".

Divisors: 1 79 2698738519 213200343001