Base | Representation |
---|---|
bin | 11111000001100101110… |
… | …001010011001010101001 |
3 | 21112211002112012200221222 |
4 | 133001211301103022221 |
5 | 234412324331414233 |
6 | 4311233223111425 |
7 | 310014140125526 |
oct | 37014561231251 |
9 | 7484075180858 |
10 | 2132011201193 |
11 | 7521a9818165 |
12 | 2a52462a2575 |
13 | 126081005783 |
14 | 752930cc14d |
15 | 3a6d26b7898 |
hex | 1f065c532a9 |
2132011201193 has 2 divisors, whose sum is σ = 2132011201194. Its totient is φ = 2132011201192.
The previous prime is 2132011201181. The next prime is 2132011201211. The reversal of 2132011201193 is 3911021102312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1998174490624 + 133836710569 = 1413568^2 + 365837^2 .
It is a cyclic number.
It is not a de Polignac number, because 2132011201193 - 226 = 2131944092329 is a prime.
It is a super-4 number, since 4×21320112011934 (a number of 50 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (2132011203193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066005600596 + 1066005600597.
It is an arithmetic number, because the mean of its divisors is an integer number (1066005600597).
Almost surely, 22132011201193 is an apocalyptic number.
It is an amenable number.
2132011201193 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132011201193 is an equidigital number, since it uses as much as digits as its factorization.
2132011201193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 26.
The spelling of 2132011201193 in words is "two trillion, one hundred thirty-two billion, eleven million, two hundred one thousand, one hundred ninety-three".
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